Fig. 13.4 An electric field F > 0 applied in the positive x-direction, perpendicular to the metal surface which lies in the plane x = 0. In (a), the field is zero. In (b), the field is not zero, and enables the value of a2 to be calculated.As before, we have regions I, II, and III, with a1 = 0. The value of a2 is given by −W = −qFa2, or a2 = W/(qF). Hence
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