METHAMPHETAMINE FAQ v1.0:1. via Chl

METHAMPHETAMINE FAQ v1.0:

1. via Chloromethamphetamine notes
with Bromomethamphetamine extension.
2. via Iodomethamphetamine notes
3. P2P notes [none yet other than "reductively aminate"]
4. via D-Phenylalanine notes
[or DL-Phenylalanine]
5. via Amphetamine
6. Seperation of isomers of amphetamine and related
7. "Bunk" synthesises, and why they don't work
8. General information

...........................(1) Via Chloromethamphetamine...................

Making it from ephedrine or pseudoephedrine is possible. The only
difference between methamphetamine and (pseudo)ephedrine is that damn
alpha-hydroxy group. Reacting your ephedrine with thionyl chloride
replaes the OH with Cl to produce N-methyl-alpha-chloroamphetamine as an
intermediate. Hydrogenating this product is easy: use lithium aluminum
hydride, sodium borohydride, or even hydrogen gas with nickel or platinum
metal as a catalyst. The product of this step is N-methylamphetamine and
HCl. Evaporate off the water and you have methamphetamine hydrochloride.

Another method:
React the (pseud)Ephedrine with PHOSPHORUS PENTACHLORIDE (maybe even
the trichloride would work!). This is another chlorinating agent. The
byproduct is phosphoric acid instead of messy sulphur compounds. In other
words, LESS STINK!!!
Reduction is possible with standard LAH procedures, as per above.
/////////////////////A bromomethamphetamine side note, possibly appliable
to the chloroamphetamine methods with altered yields///////
> Would you be so kind as to e-mail me a detailed description of the
> brominated ephedrine method of synthesizing methamphetamine. Thanx!
Method, no. The idea I proposed was to prepare HBr acid [see elusis's
file] in aqueous solution, add Ephedrine base (or HBr?) and zinc bromide
[or a small amount of zinc to FORM zinc bromide] as catalyst, to form
bromomethamphetamine. This reaction would take place faster than the
coresponding reaction with HCl.
note that HI + ZnI may very well proceed straight to methamphetamine
given HI's aptitude for attacking iodated hydrocarbons.
The bromomethamphetamine would be disolved in anhydrous ethyl ether, then
powdered magnesium would be added, hopefully forming the grignard. To
this water is added slowly to form methamphetamine and various magnesium
salts..
I've never seen it tried and the NH2+ may cause a problem with forming the
grignard. It's just an idea.


............................(2) Via Iodomethamphetamine....................

(pseud)Ephedrine is reduced with red phosphorus using iodine as a catalyst.

OK, remember the reagent for halide sub. of an alcohol?
It was always PCl3, PBr3, or PI3 right?
Neat P(x)3 isn't usually used, right?

So, I imagine you would mix HI, red P, and the alcohol in a flask at first.
Then the P4 would change to PI3. (no, not by magic. do you remember this
shit yet?) The PI3 would reduce the alcohol to a halide by some mech. I
forgot. The PI3 again magically changes to H3PO3 and HI when heated.
The HI reduces the alcohol-that-is-now-a-halide to a hydrocarbon.

SO... The reaction basically goes like this:

Phosphorus + Iodine ---> PI3
(pseud)Ephedrine + PI3 ---> Phosphoric acid + b-Iodo,n-methamphetamine
PI3 + water ---> HI + H3PO3
b-Iodo,n-methamphetamine + HI ---> Methamphetamine + I2 (iodine)
(iodine is reused)

Another version of this synthesis involves reacting iodine with plain
old red phosphorus, adding the ephedrine, then continuing to add red P
to keep the reduction going. This is the 'classic biker meth' recipe,
and without a good acid/base extraction thru a nonpolar solvent, a good
way to end up a hyperthyroid mess with the nickname 'goiter joe']. Since,
nou doubt, the classic "biker methheads" eyeballed amounts for their
reagents [just kidding guys], and evaluated production not with scales and
chromatographs but with HONEST TO GOD FIELD TESTING [heh heh] of the
compound, there were no amounts listed. Figure it out yerself, as directed
to in the below listing:
///////////////////////////////////////////////////////////////////////////
This whole thread has been extremely educational to an old P2P chemHacker
like POPEYE, but I think y'all need to know that the HI reduction of
ephedrine doesn't involve a chlorephedrine intermediate or hydrogenation w/
Pd/C, Raney Nickel,and especially not LAH.
Now I could be fullaShit, BUT, it seems that at LEAST two syntheses are
being confused here.
The original question was:
> Will hydroiodic acid really reduce ephedrine to methamphetamine via
> beta-iodo-methamphetamine?
POPEYE doesn't know shit about anything following the 'via' in that
sentence, but he does know that L-ephedrine is refluxed with hydriodic acid
in the presence of a RED PHOSPHOROUS catalyst for 32 hours to yield crank
oil, which is seperated from the reaction goop with 10% LYE and a sep
funnel, then acidified, dehydrated, and cooled in an ether-acetone
solution to yield Crystal.. much simpler than Yall are makin' it out to be.
This is the famous one-step biker crank and it's killer when done as an art
form...considerably more potent than a P2P route and absoLUTEly the reason
that L-ephedrine has become scarce in some sectors of the occupied
territories formerly known as the USA.
Sorry I couldn't supply references or proportions for this synth....It
should be easy to Mole out from what I've said, and I absolutely 100% can
guarantee that this is not bullshit.
\\\\\\\\\\\\\\\\\\


Always watch out for beta-halogenated byproduct - these unreacted components
are supposedly quite bad for you. A LAH wash of the finished compound should
remove them nicely. Barring that, a quick reflux in 1M NaOH(aq) will probably
convert any beta-halogenated product back into ephedrine - strive to use
enough phosphorus to complete the original reaction.

YET ANOTHER METHOD:
Alcohols can be converted to their halides simply by mixing with the acid.
Tert-butanol reacts SO FAST that merely mixing it with HCl results in tert-
butyl-chloride in a few minutes! In general, the rules for this are that
tertiary alcohols react fastest, and primary alcohols slowest. N-butanol +
HCl reacts so slowly that Zinc Chloride must be used as a catalyst. Another
thing to remember is that HI reacts fastest, HCl slowest.

With this in mind, recall that Hx halogen acids can be synthesized from
their salts and a stronger acid. Sulphuric acid is suitable for HCl and
sometimes HBr, but will oxidize HI back to I2. Phosphoric acid however will
not, and can be used with solid KI or NaI to make HI gas.

The ideal reaction to use for this method would probably involve zinc iodide
and hydroiodic acid. Zinc iodide can be prepared by simply mixing zinc and
iodine in a suitable setting and heating (dangerous enough - exothermic rxn).
Make enough zinc iodide and you can use it...
Zinc Iodide + Phosphoric acid ---> Zinc Phosphate + HI (gas)

ZnI
HI + Ephedrine ---> b-iodomethamphetamine + H2O

HI + b-iodomethamphetamine ---> methamphetamine

A suggested synthesis would involve leaving the HI + Ephedrine over ZnI
for for a LONG TIME [two days?], perhaps even with heating? As with
all proposed synthesises, try it first, find out, and use your intuition
to think of an improvement, try that, see if it works better or worse, etc.


...................................(3) P2P Notes...........................


.............................(4) Via D,L-Phenylalanine.....................

A surprisingly simple synthesis is possible from the amino acid
phenylalanine, which is available at health food stores for about $14 for
100 tablets. Phenylalanine is 2-amino-3-phenylpropanoic acid, which is
more or less amphetamine with a COOH where the CH3 should be at the end of
the chain. Thionyl chloride will replace the OH with a Cl, which falls off
and is replaced by H when you give it lithium aluminum hydride, sodium
borohydride, or hydrogen gas and nickel/platinum. If you use hydrogen and
metal for that step, you'll have to reduce the carbonyl group with one of
the hydrides, so best save time + effort and use them and do both
reductions at once. When that carbonyl is reduced, you now have
amphetamine. Go back up to that first one I mentioned for upgrading
amphetamine into methamphetamine. (and end up with a racemic mixture - that
is to say dl-amphetamine or dl-methamphetamine - the latter being similar
to 50% d-meth from ephedrine and 50% l-meth from a vicks inhaler!]
[BY THE WAY: If you use the all-to-common L-Phenylalanine, you'll get
l-amphetamine! Use "DL-Phenylalanine (DLPA)" if you want to use this
prcedure]

Note that both the DLPA and the P2P procedures will give you a mixture
of d- and l- isomers. The d- is cool, the l- is shit. If you have the
time, energy, and equipment, you can separate the two.

|and reprocess the l- into d- by oxidizing it and re-aminating it as
|described in the "critique" of the Phrack synthesis.
Why bother? what a major pain in the ass, especially considering the
ease of producing the d-isomer directly, the cheapness of DLPA versus
recycling L-meth into more racemic product, etc. Simply isolate
the D-isomer and THROW the L-isomer AWAY!!!


................................(5) Via Amphetamine........................

One of the easiest ways to make methamphetamine is from amphetamine. Of
course, this assumes you have amphetamine in the first place, but let's
just pretend you have some and you want to spice it up a bit.
The difference between amphetamine and methamphetamine is the addition of
a single methyl group (CH3) to the amino group sticking off the middle
carbon atom in the chain. Fortunately, substituting amines is really
simple. Vaporize your amine (your amphetamine) with a bunch of vaporized
chloromethane (CH3Cl, a solvent) and some gaseous pyridine...
voila, the amino group takes the methyl from the chlorometha

Kết quả (Việt) 1:

METHAMPHETAMINE FAQ v1.0:1. via Chloromethamphetamine notes with Bromomethamphetamine extension.2. via Iodomethamphetamine notes3. P2P notes [none yet other than "reductively aminate"]4. via D-Phenylalanine notes [or DL-Phenylalanine]5. via Amphetamine6. Seperation of isomers of amphetamine and related7. "Bunk" synthesises, and why they don't work8. General information...........................(1) Via Chloromethamphetamine...................Making it from ephedrine or pseudoephedrine is possible. The only difference between methamphetamine and (pseudo)ephedrine is that damn alpha-hydroxy group. Reacting your ephedrine with thionyl chloride replaes the OH with Cl to produce N-methyl-alpha-chloroamphetamine as an intermediate. Hydrogenating this product is easy: use lithium aluminum hydride, sodium borohydride, or even hydrogen gas with nickel or platinum metal as a catalyst. The product of this step is N-methylamphetamine and HCl. Evaporate off the water and you have methamphetamine hydrochloride.Another method:React the (pseud)Ephedrine with PHOSPHORUS PENTACHLORIDE (maybe eventhe trichloride would work!). This is another chlorinating agent. Thebyproduct is phosphoric acid instead of messy sulphur compounds. In otherwords, LESS STINK!!!Reduction is possible with standard LAH procedures, as per above./////////////////////A bromomethamphetamine side note, possibly appliable to the chloroamphetamine methods with altered yields///////> Nào bạn như vậy loại như e-mail cho tôi một mô tả chi tiết của các > brôm ephedrin phương pháp tổng hợp methamphetamine. Thanx!Phương pháp, không có. Ý tưởng tôi đề nghị là để chuẩn bị HBr axit [xem của elusis tập tin] trong dung dịch nước, thêm ephedrin cơ sở (hoặc HBr?) và kẽm bromua [hoặc một số lượng nhỏ của kẽm để tạo thành kẽm bromua] như chất xúc tác, để tạo thành bromomethamphetamine. Phản ứng này sẽ diễn ra nhanh hơn so với các coresponding phản ứng với HCl. lưu ý rằng HI + ZnI có thể rất tốt tiếp tục thẳng đến methamphetamine đưa ra của HI aptitude để tấn công iodated hydrocarbon.Bromomethamphetamine sẽ là disolved trong Khan ethyl ether, sau đó magnesium bột sẽ được thêm vào, Hy vọng tạo thành grignard. Để nước này được thêm từ từ vào mẫu methamphetamine và nhiều magiê muối...Tôi đã không bao giờ nhìn thấy nó đã cố gắng và NH2 + có thể gây ra một vấn đề với hình thành các Grignard. Nó là chỉ là một ý tưởng............................. (2) thông qua Iodomethamphetamine...(pseud) Ephedrin là giảm với phốt pho đỏ iốt sử dụng như một chất xúc tác.Được rồi, nhớ tinh khiết cho halua phụ. một rượu?Nó luôn luôn là Pbr3, PBr3, hoặc PI3 right?Gọn gàng P (x) 3 không phải là thường được sử dụng, phải không?Vì vậy, tôi tưởng tượng bạn sẽ trộn HI, đỏ P và rượu trong một flask lúc đầu tiên.Sau đó P4 sẽ thay đổi để PI3. (không, chứ không phải bởi magic. bạn có nhớ này chết tiệt chưa?) PI3 sẽ làm giảm rượu đến halua một bởi một số mech. Tôi forgot. The PI3 again magically changes to H3PO3 and HI when heated.The HI reduces the alcohol-that-is-now-a-halide to a hydrocarbon.SO... The reaction basically goes like this:Phosphorus + Iodine ---> PI3(pseud)Ephedrine + PI3 ---> Phosphoric acid + b-Iodo,n-methamphetaminePI3 + water ---> HI + H3PO3b-Iodo,n-methamphetamine + HI ---> Methamphetamine + I2 (iodine) (iodine is reused)Another version of this synthesis involves reacting iodine with plain old red phosphorus, adding the ephedrine, then continuing to add red Pto keep the reduction going. This is the 'classic biker meth' recipe, and without a good acid/base extraction thru a nonpolar solvent, a good way to end up a hyperthyroid mess with the nickname 'goiter joe']. Since,nou doubt, the classic "biker methheads" eyeballed amounts for theirreagents [just kidding guys], and evaluated production not with scales andchromatographs but with HONEST TO GOD FIELD TESTING [heh heh] of thecompound, there were no amounts listed. Figure it out yerself, as directedto in the below listing:///////////////////////////////////////////////////////////////////////////This whole thread has been extremely educational to an old P2P chemHackerlike POPEYE, but I think y'all need to know that the HI reduction ofephedrine doesn't involve a chlorephedrine intermediate or hydrogenation w/Pd/C, Raney Nickel,and especially not LAH.Now I could be fullaShit, BUT, it seems that at LEAST two syntheses arebeing confused here.The original question was:> Will hydroiodic acid really reduce ephedrine to methamphetamine via > beta-iodo-methamphetamine?POPEYE doesn't know shit about anything following the 'via' in thatsentence, but he does know that L-ephedrine is refluxed with hydriodic acidin the presence of a RED PHOSPHOROUS catalyst for 32 hours to yield crankoil, which is seperated from the reaction goop with 10% LYE and a sepfunnel, then acidified, dehydrated, and cooled in an ether-acetonesolution to yield Crystal.. much simpler than Yall are makin' it out to be.This is the famous one-step biker crank and it's killer when done as an artform...considerably more potent than a P2P route and absoLUTEly the reasonthat L-ephedrine has become scarce in some sectors of the occupiedterritories formerly known as the USA.Sorry I couldn't supply references or proportions for this synth....Itshould be easy to Mole out from what I've said, and I absolutely 100% canguarantee that this is not bullshit.\\\\\\\\\\\\\\\\\\Always watch out for beta-halogenated byproduct - these unreacted componentsare supposedly quite bad for you. A LAH wash of the finished compound shouldremove them nicely. Barring that, a quick reflux in 1M NaOH(aq) will probablyconvert any beta-halogenated product back into ephedrine - strive to useenough phosphorus to complete the original reaction.YET ANOTHER METHOD:Alcohols can be converted to their halides simply by mixing with the acid.Tert-butanol phản ứng quá nhanh mà chỉ đơn thuần là trộn nó với HCl kết quả trong tert-Butyl – clorua trong vài phút! Nói chung, các quy tắc này là màĐại học rượu phản ứng nhanh nhất, và chính rượu chậm nhất. N-butanol + HCl phản ứng rất chậm kẽm clorua phải được sử dụng như một chất xúc tác. Khácđiều cần nhớ là rằng HI phản ứng nhanh nhất, HCl chậm nhất.Với điều này trong tâm trí, nhớ lại rằng Hx halogen axit có thể được tổng hợp từCác muối và axit mạnh mẽ hơn. Axít sunfuric là thích hợp cho HCl vàđôi khi HBr, nhưng sẽ ôxy hóa HI quay lại I2. Axít phốtphoric Tuy nhiên sẽkhông, và có thể được sử dụng với rắn KI hoặc NaI để kiếm HI khí.Phản ứng lý tưởng để sử dụng cho phương pháp này có lẽ sẽ liên quan đến kẽm iođuavà hydroiodic axít. Kẽm iođua có thể điều chế bằng cách trộn chỉ đơn giản là kẽm vàiốt trong một thiết lập thích hợp và hệ thống sưởi (nguy hiểm đủ - rxn tỏa nhiệt).Làm cho đủ iođua kẽm và bạn có thể sử dụng nó...Kẽm iođua + axit photphoric---> kẽm Phosphate + HI (khí) ZnIHI + ephedrin---> b-iodomethamphetamine + H2OHI + b-iodomethamphetamine---> methamphetamineMột tổng hợp đề nghị nào liên quan đến để lại HI + ephedrin trên ZnIcho một thời gian dài [hai ngày?], có lẽ ngay cả với hệ thống sưởi? Như với Tất cả đề nghị synthesises, hãy thử nó đầu tiên, tìm hiểu và sử dụng trực giác của bạnsuy nghĩ của một cải tiến, thử mà xem nếu nó hoạt động tốt hơn hoặc tệ hơn, vv.................................... (3) P2P ghi chú................................ (4) thông qua D, L-nmol...Một tổng hợp đáng ngạc nhiên đơn giản có thể từ các axit aminnmol, đó là có sẵn tại y tế thực phẩm mua sắm cho khoảng $14 cho100 viên nén. Nmol là 2-amino-3-phenylpropanoic axit, đó làhơn amphetamine với một COOH nơi CH3 nên vào giữaChuỗi. Thionyl clorua sẽ thay thế OH với một Cl, rơi khỏivà được thay thế bởi H khi bạn cung cấp cho nó hiđrua nhôm liti, natribohiđrua, hoặc khí hiđrô và niken/bạch kim. Nếu bạn sử dụng hydro vàkim loại cho rằng bước, bạn sẽ cần phải giảm nhóm cacbonyl với một tronghiđrua, vì vậy tốt nhất tiết kiệm thời gian + nỗ lực và sử dụng chúng và làm cả haicắt giảm cùng một lúc. Khi đó cacbonyl là giảm, bây giờ bạn cóamphetamine. Quay lại lên để là người đầu tiên tôi đề cập để nâng cấpamphetamine vào methamphetamine. (và kết thúc với một hỗn hợp racemic - màđể nói dl-amphetamine hoặc dl-methamphetamine - đang được thứ hai tương tự đến 50% d-meth từ ephedrin và 50% l-meth từ một inhaler vicks!][BY THE WAY: nếu bạn sử dụng tất cả phổ biến L-nmol, bạn sẽ nhận được l-amphetamine! Sử dụng "DL-nmol (DLPA)" nếu bạn muốn sử dụng điều này prcedure]Lưu ý rằng DLPA và các thủ tục P2P sẽ cho bạn một hỗn hợp của d - và l-siêu ổn định. D - là mát mẻ, l - là shit. Nếu bạn có các thời gian, năng lượng và thiết bị, bạn có thể tách riêng hai. |and tái xử lý l - vào d-bởi ôxi hóa nó và re-aminating nó là |described trong "phê bình" tổng hợp Phrack.Tại sao bận tâm? những gì một nỗi đau lớn trong ass, đặc biệt là xem xét các dễ dàng sản xuất d-đồng phân trực tiếp, cheapness DLPA so vớitái chế L-meth thành hơn racemic sản phẩm, v.v... Chỉ đơn giản là cô lập D-đồng phân và ném đồng phân L AWAY!................................ (5) thông qua Amphetamine...Một trong những cách dễ nhất để kiếm methamphetamine là từ amphetamine. Của Tất nhiên, điều này giả định bạn có amphetamine ở nơi đầu tiên, nhưng chúng ta hãy chỉ là giả vờ bạn có một số và bạn muốn để gia vị nó lên một chút.Sự khác biệt giữa amphetamine và methamphetamine là sự bổ sung của một nhóm methyl duy nhất (CH3) vào nhóm amin gắn bó ra giữa nguyên tử cacbon trong chuỗi. May mắn thay, thay thế amin là thực sự đơn giản. Bốc hơi của bạn amin (của bạn amphetamine) với một bó của cận chloromethane (CH3Cl, dung môi) và một số pyridin khí...thì đấy, nhóm amin mất methyl từ chlorometha