Substituting these values of the artificial variables into Eq. (12.26) abd grouping givesY= (6-15P)x1+(3-17P)x2 + Px3 + Px4+Px5+93PThe first tableau can now be constructed. In the minimization operation the variable with the largest positive difference coefficient is chosen to be programmed. In tableau 1 (table 12.10) this choice will be x2 because P appears with the largest coefficient and the P values dominate over any purely numerical terms.
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